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9x^2-45x=324
We move all terms to the left:
9x^2-45x-(324)=0
a = 9; b = -45; c = -324;
Δ = b2-4ac
Δ = -452-4·9·(-324)
Δ = 13689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13689}=117$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-117}{2*9}=\frac{-72}{18} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+117}{2*9}=\frac{162}{18} =9 $
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